SOLUTION: Kevin and Randy Muise have a jar containing 72 coins, all of which are either quarters or nickels. The total value of the coins in the jar is $11.40. How many of each type of coin

Algebra.Com
Question 972938: Kevin and Randy Muise have a jar containing 72 coins, all of which are either quarters or nickels. The total value of the coins in the jar is $11.40. How many of each type of coin do they have?
Answer by macston(5194)   (Show Source): You can put this solution on YOUR website!
.
Q=number of quarters; N=number of nickels
Q+N=72
Q=72-N Use this to substitute for Q
.
$0.25Q+$0.05N=$11.40 Substitute for Q.
$0.25(72-N)+$0.05N=$11.40
$18.00-$0.25N+$0.05N=$11.40
-$0.20N=-$6.60
N=33 They have 33 nickels
Q=72-N=72-33=39 They have 39 quarters
.
CHECK:
$0.25Q+$0.05N=$11.40
$0.25(39)+$0.05(33)=$11.40
$9.75+$1.65=$11.40
$11.40=$11.40

RELATED QUESTIONS

Kevin and Randy Muise have a jar containing 79 coins, all of which are either quarters or (answered by Edwin McCravy)
kevin and randy muise have a jar containing 79 coins, all of which are either quarters or (answered by Edwin McCravy)
Kevin and Randy Muise have a jar containing 32 coins, all of which are either... (answered by ewatrrr)
Kevin and Randy Muise have a jar containing 87 coins, all of which are either quarters or (answered by TimothyLamb)
Kevin and Randy Muise have a jar containing 53 coins, all of which are either... (answered by Alan3354)
kevin and randy muise have a jar containing 34 coins, all of which are either quarters or (answered by Fombitz)
kevin and randy muise have a jar containing 31 coins, all of which are either quarters or (answered by ikleyn)
Kevin and Randy Muise have a jar containing 28 coins, all of which are either quarters... (answered by Edwin McCravy,ikleyn)
1. Kevin and randy Muise have a jar containing 70 coins. All of which are either quarters (answered by ikleyn)