SOLUTION: A man has 20 coins in his pocket consisting of 5 peso, 10 peso and 1 peso coins. There are an equal number of ones and fives among them. He has 88 pesos in all. How many coins of e

Question 969659: A man has 20 coins in his pocket consisting of 5 peso, 10 peso and 1 peso coins. There are an equal number of ones and fives among them. He has 88 pesos in all. How many coins of each denomination are there?
Answer by CubeyThePenguin(3113) (Show Source): You can put this solution on YOUR website!
(repeat question)

p = number of 1 peso coins
n = number of 5 peso coins
d = number of 10 peso coins

p = n
p + n + d = 20
p + 5n + 10d = 88

2n + d = 20
6n + 10d = 88

20n + 10d = 200
-(6n + 10d = 88)
---------------------
14n = 112
n = 8

--> 8 1-peso coins, 8 5-peso coins, 4 10-peso coins.
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