SOLUTION: Taylor has 6.70$ in quarters and dimes. If the total number of coins in her wallet is 17 how many quarters does she have

Algebra.Com
Question 965879: Taylor has 6.70$ in quarters and dimes. If the total number of coins in her wallet is 17 how many quarters does she have
Answer by Edwin McCravy(20066)   (Show Source): You can put this solution on YOUR website!
Taylor has 6.70$ in quarters and dimes. If the total number of coins in her wallet is 17 how many quarters does she have

This problem has a typo.  I think the number of coins should be 37, 
certainly not 17. I'll first do it with 17 to show you that there can be 
no way to have $6.70 in quarters and dimes with only 17 coins.  If 
you think about it, you know that's not possible because if they were all
quarters, 17 quarters is only $4.50

Then below that I'll do it changing the 17 to 37.

Let the number of quarters be x
Then the number of dimes, using
ONE PART = TOTAL MINUS OTHER PART,
is 17-x.
                      Value      Value
Type       Number       of         of
 of          of        EACH       ALL
coin        coins      coin      coins
-------------------------------------------
quarters      x        $0.25    $0.25x
dimes      17-x        $0.10    $0.25(17-x)
-------------------------------------------
TOTALS       17       -----     $6.70

 The equation comes from the column on the right

  

 0.25x + 0.10(17-x) = 6.70

Get rid of decimals by multiplying every term by 100

     25x + 10(17-x) = 670

    25x + 170 - 10x = 670

          15x + 170 = 670

               15x = 500

                 x = 33.3333333 = the number of quarters 

The number of dimes is 17-x or 17-33.3333333 or -16.3333333 dimes

You cannot have a fraction number of quarters and a negative number
of dimes.  There is no solution.


-------------------------------------------------------

Now here's the same problem using 37 coins instead of 17 coins.


Let the number of quarter be x
Then the number of dime, using
ONE PART = TOTAL MINUS OTHER PART,
is 37-x.
                      Value      Value
Type       Number       of         of
 of          of        EACH       ALL
coin        coins      coin      coins
-------------------------------------------
quarter      x         $0.25     $0.25x
dime      37-x         $0.1      $0.1(37-x)
-------------------------------------------
TOTALS      37        -----      $6.70

 The equation comes from the column on the right

  

0.25x + 0.10(37-x) = 6.70

Get rid of decimals by multiplying every term by 100

     25x + 10(37-x) = 670

    25x + 370 - 10x = 670

          15x + 370 = 670

               15x = 300

                 x = 20 = the number of quarters

The number of dimes is 37-x or 37-20 or 17 dimes

Edwin


RELATED QUESTIONS

jennifer has only two types of coins in her wallet, quarters and dimes. she has twice as... (answered by ewatrrr)
Cookie has 97 coins in her collection – all either nickels, dimes or quarters. If 77 of... (answered by Edwin McCravy)
Taylor has a box of coins that she uses when she plays poker with her friends. The box... (answered by stanbon)
Lillian has 14 coins in her wallet. They coins total $1.30. She has twice as many dimes... (answered by addingup)
taylor has $3.15 in dimes and quarters. the sum of dimes is 7 more than the number of... (answered by Alan3354)
Jenny has a total of 21 dimes and quarters in her piggy bank. If the coins are worth... (answered by josgarithmetic)
A woman has 25 coins in her pocket, all of which are dimes and quarters. If the total... (answered by ankor@dixie-net.com,Alan3354)
liviana has $ 2.20 in coins in her change purse. if there is a total of 15 coins how... (answered by josmiceli)
alice has $2.75 in quarters and dimes. if she has 4 fewer dimes than twice the number of... (answered by scott8148)