SOLUTION: Kevin and Randy Muisw have a jar containing 54 coins all of which are quarters or nickels the total value of the coins in the jar is $7.70 how Many of each coin do they have?

Algebra.Com
Question 962643: Kevin and Randy Muisw have a jar containing 54 coins all of which are quarters or nickels the total value of the coins in the jar is $7.70 how Many of each coin do they have?
Answer by CubeyThePenguin(3113)   (Show Source): You can put this solution on YOUR website!
q = number of quarters
n = number of nickels

n + q = 54
5n + 25q = 770

25n + 25q = 1350
-5n - 25q = -770
-------------------
20n = 580
n = 29

There are 29 nickels and 25 quarters.

RELATED QUESTIONS

Kevin and Randy Muise have a jar containing 79 coins, all of which are either quarters or (answered by Edwin McCravy)
kevin and randy muise have a jar containing 79 coins, all of which are either quarters or (answered by Edwin McCravy)
Kevin and Randy have a jar containing 33 coins, all of which are either quarters or... (answered by richwmiller)
Kevin and Randy Muise have a jar containing 32 coins, all of which are either... (answered by ewatrrr)
Kevin and Randy Muise have a jar containing 87 coins, all of which are either quarters or (answered by TimothyLamb)
Kevin and Randy Muise have a jar containing 53 coins, all of which are either... (answered by Alan3354)
Kevin and Randy Muise have a jar containing 72 coins, all of which are either quarters or (answered by macston)
kevin and randy muise have a jar containing 34 coins, all of which are either quarters or (answered by Fombitz)
kevin and randy muise have a jar containing 31 coins, all of which are either quarters or (answered by ikleyn)