Question 959277: A piggy bank contains $18.30 made up of loonies, quarters, and nickels. There are 3 more quarters than loonies and twice as many nickels than loonies. How many of each coin are there?
Found 3 solutions by macston, josgarithmetic, MathTherapy:
Answer by macston(5194)   (Show Source):
You can put this solution on YOUR website! L=loonies; Q=quarters=L+3; N=nickels=2L
$1L+$0.25Q+$0.05N=$18.30 Substitute for Q and N
$1L+$0.25(L+3)+$0.05(2L)=$18.30
$1L+$0.25L+$0.75+$0.10L=$18.30 Subtract $0.75 from each side.
$1.35L=$17.55 Divide each side by $1.35
L=13 ANSWER 1: There were 13 loonies.
Q=L+3=13+3=16 ANSWER 2: There were 16 quarters.
N=2L=2(13)=26 ANSWER 3: There were 26 nickels.
CHECK:
$1L+$0.25Q+$0.05N=$18.30
$1.00(13)+$0.25(16)+$0.05(26)=$18.30
$13.00+$4.00+$1.30=$18.30
$18.30=$18.30
Answer by josgarithmetic(39617)  (Show Source):
You can put this solution on YOUR website! The value of one loony is unknown. Let L = fraction of dollar for 1 loony, which may be mixed or whole value.
Let x be how many loonies.
Three equations in four unknown variables, L, x, q, n.
 , not a linear equation. Solutions must use x as a whole number. L must be a positive real number RATIONAL
 , now this equation form allows picking any of several whole number values for x, and finding any fitting values for L.
 , and notice that there is a restriction here for x and for L, again, L must be positive. Necessary,  .
Answer by MathTherapy(10552)  (Show Source):
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