SOLUTION: Jar containing 66 coins, all which are either quarters or nickels. Total value of coins in the jar is 7.30. The jar contains how many quarters ? And how many nickels ?

SOLUTION: Jar containing 66 coins, all which are either quarters or nickels. Total value of coins in the jar is 7.30. The jar contains how many quarters ? And how many nickels ?

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Question 956439: Jar containing 66 coins, all which are either quarters or nickels. Total value of coins in the jar is 7.30. The jar contains how many quarters ? And how many nickels ?
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
Q+N=66
0.25Q+0.05N=7.30
N=66-Q
0.25Q+0.05(66-Q)=7.30
.25Q+3.30-.05Q=7.30
.20Q=7.30-3.30
.20Q=4.00
Q=4.00/.20
Q=20 QUARTERS.
20+N=66
N=66-20
N=46 NICKELS.
PROOF:
.25*20+.05*46=7.30
5.00+2.30=7.30
7.30=7.30
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