SOLUTION: A newspaper carrier has $4.90 in change. He has five more quarters than dimes but five times as many nickels as quarters. How many coins of each type does he have?

Question 955197: A newspaper carrier has $4.90 in change. He has five more quarters than dimes but five times as many nickels as quarters. How many coins of each type does he have?
Answer by CubeyThePenguin(3113) (Show Source): You can put this solution on YOUR website!
n = number of nickels
d = number of dimes
q = number of quarters

5n + 10d + 25q = 490
q = d + 5
n = 5q

Write everything in terms of d.

5(5(d+5)) + 10d + 25(d+5) = 490
25d + 125 + 10d + 25d + 125 = 490
60d = 240
d = 4

There are 45 nickels, 4 dimes, and 9 quarters.
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