SOLUTION: Little Melinda has nickels and quarters in her bank. She has four fewer nickels than quarters. She has $3.70 in the bank. How many coins of each type does she have?

Question 954393: Little Melinda has nickels and quarters in her bank. She has four fewer nickels than quarters. She has $3.70 in the bank. How many coins of each type does she have?
Answer by macston(5194) (Show Source): You can put this solution on YOUR website!
Q=quarters; N=nickels=Q-4
$0.25Q+$0.05N=$3.70 Substitute for N.
$0.25Q+$0.05(Q-4)=$3.70
$0.25Q+$0.05Q-$0.20=$3.70 Add $0.20 to each side.
$0.30Q=$3.90 Divide each side by $0.30
Q=13 ANSWER 1: There were 13 quarters.
N=Q-4=13-4=9 ANSWER 2: There were 9 nickels.
CHECK:
$0.25Q+$0.05N=$3.70
$0.25(13)+$0.05(9)=$3.70
$3.25+$0.45=$3.70
$3.70=$3.70
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