SOLUTION: Ernie has $3.35 in nickels and dimes. He has thirteen more nickels than dimes. How many of each coin does he have?

Question 953653: Ernie has $3.35 in nickels and dimes. He has thirteen more nickels than dimes. How many of each coin does he have?
Answer by macston(5194) (Show Source): You can put this solution on YOUR website!
n=nickels; d=dimes=n-13
$0.05n+$0.10d=$3.35 Substitute for d.
$0.05n+$0.10(n-13)=$3.35
$0.05n+$0.10n-$1.30=$3.35 Add $1.30 to each side.
$0.15n=$4.65 Divide each side by $0.15.
n=31 ANSWER 1: There were 31 nickels.
d=n-13=31-13=18 ANSWER 2: There were 18 dimes.
CHECK
$0.05n+$0.10d=$3.35
$0.05(31)+$0.10(18)=$3.35
$1.55+$1.80=$3.35
$3.35=$3.35

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