SOLUTION: Sean has $11.00 in toonies and loonies. He has 10 coins altogether. How many coins of each kind does he have?

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Question 950369: Sean has $11.00 in toonies and loonies. He has 10 coins altogether. How many coins of each kind does he have?

Answer by macston(5194)   (Show Source): You can put this solution on YOUR website!
L= number of loonies; T= number of toonies
L+T=10
T=10-L
$1L+$2T=$11 Substitute for T
$1L+$2(10-L)=$11
$1L+$20-$2L=$11 Add $1L to each side
$20=$11+$1L Subtract $11 from each side.
$9=$1L Divide each side by $1 (Removes the units)
9=L ANSWER 1: There are 9 loonies.
T=10-L=10-9=1 ANSWER 2: There is 1 toonie.

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