SOLUTION: Kendra has $3.60 in dimes and nickels. If she has 4 times as many dimes as nickels, how many of each coin does she have? Please help! I've been working on this math problem for

Question 948715: Kendra has $3.60 in dimes and nickels. If she has 4 times as many dimes as nickels, how many of each coin does she have?
Please help! I've been working on this math problem for HOURS. I've set it up in different ways and haven't been able to get the answer. The way I have it set is: 4x (dimes)+10x(value of dime)+5x(value of nickle)+x(unknown nickles)=360
Thank you for your time and your help!
Found 3 solutions by macston, josgarithmetic, MathTherapy:
Answer by macston(5194)   (Show Source): You can put this solution on YOUR website!
N=number of nickels; D=number of dimes=4N
$0.05N+$0.10D=$3.60 Substitute for D
$0.05N+$0.10(4N)=$3.60
$0.05N+$0.40N=$3.60
$0.45N=$3.60 Divide each side by $0.45
N=8 ANSWER 1: There were 8 nickels
D=4N=4(8)=32 ANSWER 2: There were 32 dimes
CHECK
$0.05N+$0.10D=$3.60
$0.05(8)+$0.10(32)=$3.60
$0.40+$3.20=$3.60
$3.60=$3.60
Answer by josgarithmetic(39620)   (Show Source): You can put this solution on YOUR website!
d, how many dimes
n, how many nickels

The description is transcribable into this system of equations:

Simplify the system and solve for the two variables.

The money count equation should go something like this:

'

'
The coin relationship equation should be easily understood as this:
, which can easily be substituted into the simplified money count equation.....
Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

Kendra has $3.60 in dimes and nickels. If she has 4 times as many dimes as nickels, how many of each coin does she have?
Please help! I've been working on this math problem for HOURS. I've set it up in different ways and haven't been able to get the answer. The way I have it set is: 4x (dimes)+10x(value of dime)+5x(value of nickle)+x(unknown nickles)=360
Thank you for your time and your help!

Let number of nickels be N
Then number of dimes = 4N
We then get the value equation: .05N + .1(4N) = 3.6
.05N + .4N = 3.6
.45N = 3.6
N, or number of nickels = , or
Number of dimes: 4(8), or
It's much, much simpler when you use 1 variable.
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