SOLUTION: A pile of thirty-nine coins contains only dimes and quarters. The value of all the coins is $7.65. If each dime was exchanged for a nickel and each quarter exchanged for a half-dol

Question 937224: A pile of thirty-nine coins contains only dimes and quarters. The value of all the coins is $7.65. If each dime was exchanged for a nickel and each quarter exchanged for a half-dollar, what would the new value, in dollars, of the coins? Thanks for your help.
Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
x = number of dimes
y = number of quarters
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x + y = 39
10x + 25y = 765
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put the system of linear equations into standard form
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x + y = 39
10x + 25y = 765
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solution:
x = number of dimes = 14
y = number of quarters = 25
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answer:
x = number of dimes = 14*0.05 = $0.70
y = number of quarters = 25*0.50 = $12.50
0.70 + 12.50 = $13.20
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