SOLUTION: josh has 25 coins. these are nickels and dimes. if he has 1.95 dollars, how many of each will he have

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Question 933954: josh has 25 coins. these are nickels and dimes. if he has 1.95 dollars, how many of each will he have
Found 2 solutions by Edwin McCravy, Alan3354:
Answer by Edwin McCravy(20056)   (Show Source): You can put this solution on YOUR website!
josh has 25 coins. these are nickels and dimes. if he has 1.95 dollars, how many of each will he have
Let the number of nickels be x
Then the number of dimes, using 
ONE PART = TOTAL MINUS OTHER PART,
is 25-x.  
                      Value      Value
Type       Number       of         of
 of          of        EACH       ALL
coin        coins      coin      coins
-------------------------------------------
NICKELS      x        $0.05    $0.05x 
DIMES      25-x       $0.10    $0.10(25-x)
-------------------------------------------
TOTALS      25        -----    $1.95

 The equation comes from the column on the right

  

0.05x + 0.10(25-x) = 1.95

Get rid of decimals by multiplying every term by 100

     5x + 10(25-x) = 195

    5x + 250 - 10x = 195

         -5x + 250 = 195

               -5x = -55

                 x = 11 = the number of nickels

The number of dimes is 25-x or 25-11 or 14 dimes.

Checking:  11 nickels is $0.55 and 14 dimes is $1.40

And indeed $0.55+$1.40 = $1.95.

Edwin
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
Here's a similar problem.
===========================================
a parking lot meter contains 47 coins in dimes and quarters for a total of 5.45 . how many of each coin does the meter contain.
----------
Another method:
47 dimes would be $4.70
Each dime replaced by a quarter add 15 cents.
545 - 470 = 75 cents
75/15 = 5 quarters
42 dimes
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