SOLUTION: 14 coins, total $2.20. 5 more quarters than dimes. 3 less dimes than nickels. How many of each coin?
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Question 928641: 14 coins, total $2.20. 5 more quarters than dimes. 3 less dimes than nickels. How many of each coin?
Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
x = number of nickels
y = number of dimes
z = number of quarters
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x + y + z = 14
z = y + 5
y = x - 3
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put the system of linear equations into standard form
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x + y + z = 14
y - z = -5
x - y = 3
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copy and paste the above standard form linear equations in to this solver:
https://sooeet.com/math/system-of-linear-equations-solver.php
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solution:
x = 5
y = 2
z = 7
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check:
5x + 10y + 25z = 220
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