SOLUTION: Dan has 21 coins, all nickels, dimes, and quarters worth $3.35. If he has 4 more quarters than dimes, how many of each coin does he have?
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Question 924092: Dan has 21 coins, all nickels, dimes, and quarters worth $3.35. If he has 4 more quarters than dimes, how many of each coin does he have?
Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
x = nickels
y = dimes
z = quarters
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x + y + z = 21
5x + 10y + 25z = 335
z = y + 4
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put the system of linear equations into standard form
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x + y + z = 21
5x + 10y + 25z = 335
-y + z = 4
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copy and paste the above standard form linear equations in to this solver:
https://sooeet.com/math/system-of-linear-equations-solver.php
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solution:
x = nickels = 5
y = dimes = 6
z = quarters = 10
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