SOLUTION: A coin bank has 250 coins,dimes, quarters, worth $42.25. How many of each type of coin are there?
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Question 923872: A coin bank has 250 coins,dimes, quarters, worth $42.25. How many of each type of coin are there?
Found 2 solutions by TimothyLamb, Cromlix:
Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
x = dimes
y = quarters
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x + y = 250
10x + 25y = 4225
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put the system of linear equations into standard form
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x + y = 250
10x + 25y = 4225
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copy and paste the above standard form linear equations in to this solver:
https://sooeet.com/math/system-of-linear-equations-solver.php
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solution:
x = dimes = 135
y = quarters = 115
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Solve systems of linear equations up to 6-equations 6-variables:
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Answer by Cromlix(4381) (Show Source): You can put this solution on YOUR website!
A coin bank has 250 coins,dimes, quarters, worth $42.25
x + y = 250..................(1)
10x + 25y = 4225..............(2)
Multiply (1) by 25
25x + 25y = 6250.............(1)
10x + 25y = 4225.............(2)
Subtract (2) from (1)
15x = 2025
x = 135
Substitute x = 135 into (1)
x + y = 250
135 + y = 250
y = 250 - 135
y = 115
135 dimes and 115 quarters.
Hope this helps.
:-)
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