SOLUTION: letty has $5 in nickels, dimes and quarters. She has 3 times as many nickels as dimes. She has 5 times as much money in quarters as she does in nickels. How many of each does sh
Algebra.Com
Question 895738: letty has $5 in nickels, dimes and quarters. She has 3 times as many nickels as dimes. She has 5 times as much money in quarters as she does in nickels. How many of each does she have?
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
The count of each coin assigned variables n,d, q.
, accounts for dollar money quantity and should be simplified;
.
according to description, so .
according to description, so , meaning .
System to solve is this:
More than one solution path you can take.
Substitute for n:
-
, when substitute for n in the second equation of the listed system.
System now after eliminating n is:
Continuing,
You can work through the other equations to solve for n and q.
--
n=15, and therefore q=15.
RELATED QUESTIONS
Lisa has $5 in nickels, dimes, and quarters. She has 3 times as many nickels as dimes.... (answered by FrankM)
Nancy has 30 coins (all nickels and dimes) she has 5 times as many nickels as dimes how... (answered by ewatrrr)
Kendra has $5.40 in dimes and nickels. If she has 4 times as many dimes as nickels, how... (answered by CubeyThePenguin)
Selena has some nickels, dimes and quarters. She has 1½ times as many dimes as nickels.... (answered by josgarithmetic,macston,MathTherapy)
Kendra has $3.50 in dimes and nickels. If she has 3 times as many dimes as nickels, how... (answered by CubeyThePenguin)
Sally has 100 coins all of which are dimes, nickels, and quarters. She has $13.00 in... (answered by CubeyThePenguin)
Kendra has $4.20 in dimes and nickels. If she has 3 times as many dimes as nickels, how... (answered by richwmiller)
Kendra has $3.50 in dimes and nickels. If she has 3 times as many dimes as nickels, how... (answered by Alan3354)
Kendra has $1.75 in dimes and nickels. If she has 3 times as many dimes as nickels, how... (answered by addingup)