SOLUTION: Tim has a collection of dimes and nickles. If he has 44 more nickles than dimes and his collection is worth $29.50. Find How many nickles and dimes does he have? .10(x)=dimes .0

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Question 886276: Tim has a collection of dimes and nickles. If he has 44 more nickles than dimes and his collection is worth $29.50. Find How many nickles and dimes does he have?
.10(x)=dimes
.05(x+44)=29.50
.15x+44=29.50
15x=-14.50
x=-96.666
I keep getting a negative number am I doing something wrong?
Found 3 solutions by jim_thompson5910, MathTherapy, Alan3354:
Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
The issue occurs when you distribute.

When you go from .05(x+44) to .15x+44 it is NOT correct.

You forgot to multiply 0.05 by 44 to get 2.2
Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

Tim has a collection of dimes and nickles. If he has 44 more nickles than dimes and his collection is worth $29.50. Find How many nickles and dimes does he have?
.10(x)=dimes
.05(x+44)=29.50
.15x+44=29.50
15x=-14.50
x=-96.666
I keep getting a negative number am I doing something wrong?


.05 * x IS NOT:   .15x

.05 * 44 IS NOT:   44

You need to do correct computations!! If not you will always be WRONG!! 

Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
 Yes, you are doing something wrong. 

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