SOLUTION: You have quarters and dimes, totaling $3.10, 22 coins in all. How many of each coin do you have? I need to figure it out algebraically using substitution or elimination. I t

Question 876166: You have quarters and dimes, totaling $3.10, 22 coins in all. How many of each coin do you have?
I need to figure it out algebraically using substitution or elimination.
I thought the following would work but I can't get it right... please help!!
.25q+.10d=3.10
I feel like 22 should be involved in the equation but I'm not sure where.
Thank you in advance for any help you can give me!

Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
You have one equation, but you need 2 (2 equations needed to solve for 2 variables)

Your other equation will be d + q = 22 (# of dimes + # of quarters = total) because you have 22 coins total.

Solve d + q = 22 for q to get q = 22 - d

Then plug that into the first equation to get 0.25(22 - d) + 0.10d = 3.10

I'll let you finish up from here.
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