SOLUTION: A certain number of quarters, four times as many pennies as quarters, and six more dimes than pennies are worth $3.36. How many of each coin are there?

Question 862457: A certain number of quarters, four times as many pennies as quarters, and six more dimes than pennies are worth $3.36. How many of each coin are there?
Found 2 solutions by mananth, stanbon:
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
quarters ----------------x Numbers
pennies -----------------4x
dimes -------------------4x+6
Total value
25x+4x+10(4x+6)= 336
29x+40x+60=336
69x=336-60
69x=276
/69
x= 4
Quarters = 4
pennies = 4x=16
Dimes = 4x+6 = 16+6 =22

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A certain number of quarters, four times as many pennies as quarters, and six more dimes than pennies are worth $3.36. How many of each coin are there?
------------------------------
p = 4q
d = p + 6
---
Value Equation:
p + 10d + 25q = 336 cents
-----------------------------
p + 10(p+6) + 25(p/4) = 336
---------------------------------
11p + 60 + 25(p/4) = 336
Multiply thru by 4 to get:
----------------------------
44p + 25p = 4*276
69p = 4*276
-----
p = 16 (# of pennies)
-------------------------------
q = (1/4)p = 4 (# of quarters)
-----
d = p + 6 = 22 (# of dimes)
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Cheers,
Stan H.
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