SOLUTION: chris has $6.20 in quarters, dimes and nickels. he has three more quarters than dimes. The number of nickels is one more than twice the number of dimes. find the number of each coi

Question 85568: chris has $6.20 in quarters, dimes and nickels. he has three more quarters than dimes. The number of nickels is one more than twice the number of dimes. find the number of each coin ????
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Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!

Chris has $6.20 in quarters, dimes and nickels. he has three more quarters than dimes. The number of nickels is one more than twice the number of dimes. find the number of each coin ????
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Let number of dimes be "x"; Value of these is 10x cents
Number of quarters is "x+3"; Value of these is 25(x+3) = 25x+75 cents
Number of nickels is "2x+1"; Value of these is 5(2x+1) = 10x+5 cents
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EQUATIOn:
value + value + value = 620 cents
10x + 25x+75 + 10x+5 = 620
45x = 540
x = 12 (number of dimes)
x+3 = 15 (number of quarters)
2x+1 = 25 (number of nickels)
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Cheers,
Stan H.
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