SOLUTION: larry has a collection of nickels, dimes, and quarters totaling more than $7.50. The number of nickels is 3 times the number of dimes and the number of quarters is 4 times the numb

Question 826318: larry has a collection of nickels, dimes, and quarters totaling more than $7.50. The number of nickels is 3 times the number of dimes and the number of quarters is 4 times the number of dimes. find the least possible number of dimes in the collection.
Answer by Edwin McCravy(20056) (Show Source): You can put this solution on YOUR website!
larry has a collection of nickels, dimes, and quarters totaling more than $7.50.

$0.05n + $0.10d + $0.25q > $7.50

Clear of decimals:

          5n + 10d + 25q > 750

Divide through by 5

             n + 2d + 5q > 150

The number of nickels is 3 times the number of dimes

n = 3d

and the number of quarters is 4 times the number of dimes.

q = 4d

Substituting:

             n + 2d + 5q > 150
         3d + 2d + 5(4d) > 150
           3d + 2d + 20d > 150
                     25d > 150
                       d > 6

find the least possible number of dimes in the collection.

So the least possible number of dimes greater than 6 is 7.

Edwin

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