SOLUTION: A parking meter contains dimes and quarters worth $5.05. There are 28 coins in all. Find how many of each there are are.
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Question 810501: A parking meter contains dimes and quarters worth $5.05. There are 28 coins in all. Find how many of each there are are.
Found 2 solutions by josmiceli, richwmiller:
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Let = numbe of dimes
Let = number of quarters
-------------
(1)
(2) ( in cents )
----------------------
Multiply both sides o (1) by
and subtract (1) from (2)
(2)
(1)
and, since
(1)
(1)
There are 13 dimes and 15 quarters
--------------
check:
(2)
(2)
(2)
(2)
OK
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
25q+10d=505,
d+q=28
d=28-q
5q+2d=101
5q+2*(28-q)=101
5q+56-2q=101
3q=45
q=15
d=13
check
15*25+13*10=505
375+130=505
505=505
ok
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