SOLUTION: Jose has $4.15 in nickels and dimes. He has fourteen more nickels than dimes. How many of each coin does he have?
Algebra.Com
Question 803310: Jose has $4.15 in nickels and dimes. He has fourteen more nickels than dimes. How many of each coin does he have?
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
n=d+14,
5n+10d=415
d = 23, n = 37
RELATED QUESTIONS
Jose has $3.85 in nickels and dimes. He has 8 more nickels than dimes. How many of each... (answered by TimothyLamb)
Randy has a handful of dimes and nickels valuing $4.15.He has 7 more dimes than he has... (answered by ikleyn)
Mike has $1.75 in dimes and nickels. If he has 5 more nickels than dimes, how many of... (answered by algebrahouse.com)
Ace has $3.15 in nickels and dimes. He has 15 more nickels than dimes. How many of each... (answered by rwm)
George has $7.50 in dimes and nickels. He has 15 more nickels than dimes. How many of... (answered by stanbon,robertb,MathTherapy)
Jose has $2.45 in nickels and dimes. He has ten more nickels than dimes. How many of each (answered by stanbon)
ben has $3.40 in nickels and dimes. he has 4 more dimes than nickels. how many of each... (answered by Danielshinmath)
Ben has $3.40 in nickels and dimes. He has 4 more dimes than nickels. How many of each... (answered by stanbon)
If jon has four dollars in dimes in nickels and he has seven more dimes than nickels, how (answered by amoresroy)