SOLUTION: michael has 58 coins totaling $4.40 all nickels dimes and quarters. the number of nickels is 2 short of being 3 times the sum of the number of dimes and quarters together how many

Question 803271: michael has 58 coins totaling $4.40 all nickels dimes and quarters. the number of nickels is 2 short of being 3 times the sum of the number of dimes and quarters together how many dimes are there
Found 2 solutions by richwmiller, josmiceli:
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
similar coin problem was just submitted
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Let = number of nickels
Let = number of dimes
Let = number of quarters
----------------------------
(1)
(2) ( in cents )
(3)
-----------------------
(3)
(3)
Multiply both sides of (1) by
and add (1) and (3)
(1)
(3)

-----------
(2)
(2)
(2)
(2)
and
(3)
(3)
(3)
(3)
Subtract (3) from (2)
(2)
(3)

----------
(1)
(1)
(1)
(1)
There are 10 dimes
-----------------
check:
(2)
(2)
(2)
(2)
OK

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