I have been stuck on this question for about 45 minutes can somebody please help me?
Problem :A bank contains 44 coins (nickels, dimes, and quarters). There are twice as many dimes as nickels and 8 fewer nickels than quarters. How much money is in the bank? Thank You!
Alan didn't figure up the money, Nerdybill divided wrong and got 16
quarters instead of 17.
Let q = the number of quarters
>>,,,8 fewer nickels than quarters...<<
So the number of nickels is q-8
There are twice as many dimes as nickels
So the number of dimes is 2×(the number of nickels) = 2(q-8)
The equation comes from
So
q + (q-8) + 2(q-8) = 44
q + q - 8 + 2q - 16 = 44
4q - 24 = 44
4q = 68
q = 17 quarters
the number of nickels is q-8 = 17-8 = 9 nickels
the number of dimes = 2(q-8) = 2(17-8) = 2(9) = 18 dimes
17 quarters = $0.25(17) = $4.25
9 nickels = $0.05(9) = .45
18 dimes = $0.10(18) = 1.80
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total money = $6.50
Edwin