SOLUTION: Any help would be appreciated, thankyou! Brian has a total of 241 dimes and nickels. If he has $15.65 total in dimes and nickles, then how many nickels does he have?

Question 742999: Any help would be appreciated, thankyou!
Brian has a total of 241 dimes and nickels. If he has $15.65 total in dimes and nickles, then how many nickels does he have?
Found 2 solutions by stanbon, davethejackal:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Brian has a total of 241 dimes and nickels. If he has $15.65 total in dimes and nickles, then how many nickels does he have?
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Quantity Equation: n + d = 241
Value Equation::: 5n +10d = 1565 cents
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Modify:
n + d = 241
n +2d = 313
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Substract and solve for "d":
d = 72 (# of dimes)
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Solve for "n":
n + d = 241
n = 241-72 = 169 (# of nickels)
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Cheers,
Stan H.
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Answer by davethejackal(28) (Show Source): You can put this solution on YOUR website!
Let d= number of dimes
n = number of nickels

"a total of 241 dimes and nickels"
hence d+n = 241
or n=241-d [1]

"he has $15.65 total in dimes and nickels"
The value of a nickel is $0.05 and a dime is $0.10
hence 0.10d+0.05n=15.65 or to express it in cents 10d+5n = 1565
=> n=(1565-10d)/5= 313 -2d [2]

Combining [1] and [2]
241-d=313-2d
=> d=313-241=72

Substituting in [1] gives n=241-72 = 169

Checking in [2], the total value of the coins = 5 x 169 + 10 x 72 = 1565c or $15.65
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