SOLUTION: a pay phone is holding its maximum number of 500 coins consisting of nickels dimes and quarters. the number of quarters is twice the numbers of dimes. if the value of all the coi

Question 731966:
a pay phone is holding its maximum number of 500 coins consisting of nickels dimes and quarters. the number of quarters is twice the numbers of dimes. if the value of all the coins is $88 how many nickels were in the pay phone?
Answer by checkley79(3341) (Show Source): You can put this solution on YOUR website!
Q+D+N=500 OR 2D+D+N=500 OR 3D+N=500 0R N=500-3D
Q=2D
.25Q+.10D+.05N=88
.25*2D+.10D+.05(500-3D)=88
.50D+.10D+25-.15D=88
.45D=88-25
.45D=63
D=63/.45
D=140 DIMES.
Q=2*140=280 QUARTERS.
280+140+N=500
N=500-280-140
N=80 NICKELS.
PROOF:
.25*280+.10*140+.05*80=88
70+14+4=88
88=88

RELATED QUESTIONS
a pay phone is holding its maximum number of 500 coins consisting of nickels, dimes and... (answered by jonvaliente)

A pay phone is holding a maximum number of 500 coins consisting of nickels, dimes and... (answered by checkley71)

a payphone is holding the maximum amount of 500 coins consisting of quarters, dimes and... (answered by josmiceli)

A payphone is hold its maximum number of 500 coins consisting of nickels, dimes, and... (answered by rothauserc,addingup,Alan3354)

17 coins consisting of nickels dimes and quarters are collected for a newspaper vending... (answered by mangopeeler07)

A cashier has 25 coins consisting of nickels, dimes, and quarters with a value of $4.90.... (answered by stanbon)

SOLVE USING DETERMINANTS and CRAMER'S RULE A coin collector has 41 coins consisting of (answered by pjalgeb)

A child is holding nickels, dimes and quarters in his hand that add up to $4.95 There are (answered by richwmiller,drk)

70. Nickels, dimes, and quarters. Bernard has 41 coins consisting of nickels, dimes, and... (answered by macston)