SOLUTION: I have $1 coin, $5 coin and a 25c. $1 coin is 3 more than thrice the number of $5 coin. If I have a total of 24 coins, how many $5 do I have if the total money I have is $36.25?

Question 697510: I have $1 coin, $5 coin and a 25c. $1 coin is 3 more than thrice the number of $5 coin. If I have a total of 24 coins, how many $5 do I have if the total money I have is $36.25?
In my calculation the answer is 5. There are 5 $5 coins.
If that is true, my collection of coins doesn't sum up to $36.25.
So what's the correct answer?
Answer by htmentor(1343) (Show Source): You can put this solution on YOUR website!
Let a = the number of 25c coins
Let b = the number of $1 coins
Let c = the number of $5 coins
Given: b = 3c + 3 [3 more than thrice the number of $5 coins]
The total number of coins is 24 -> a + b + c = 24
And the total amount is 36.25 -> 0.25a + b + 5c = 36.25
Substitute the value for b in the last two equations:
a + (3c+3) + c = 24
0.25a + (3c+3) + 5c = 36.25
Collect terms:
a + 4c = 21
0.25a + 8c = 33.25
We have two equations and two unknowns
Use whatever method you choose to solve for c
Ans: c = 4
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