SOLUTION: Suppose you have 36 coins in a jar consisting entirely of dimes and quarters, worth a total of $6.75. How many dimes are in the jar? Type in your numerical answer only; do not type

Question 695619: Suppose you have 36 coins in a jar consisting entirely of dimes and quarters, worth a total of $6.75. How many dimes are in the jar? Type in your numerical answer only; do not type any words or letters with your answer.
Answer by checkley79(3341) (Show Source): You can put this solution on YOUR website!
Q+D=36
Q=36-D
.25Q+.10D=6.75
.25(36-D)+.10D=6.75
9.00-.25D+.10D=6.75
-.15D=6.75-9.00
-.15D=-2.25
D=-2.25/-.15
D=15 NUMBER OF DIMES.
Q=36-15=21 NUMBER OF QUARTERS.
PROOF:
.25*21+.10*15=6.75
5.25+1.50=6.75
6.75=6.75
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