SOLUTION: Consider the following problem: You stop on the street between errands to engage in a shell game with a street vendor. The vendor shows you a two-headed penny under one shell, a tw

Question 681675: Consider the following problem: You stop on the street between errands to engage in a shell game with a street vendor. The vendor shows you a two-headed penny under one shell, a two-tailed penny under the second shell and a fair penny (one head and one tail) under the third shell. He shuffles the shells around and then you choose a shell. He shows you that under the shell is a penny with the head side up. He is willing to bet you $5 that it is the two-headed penny. He says it cannot be the two-tailed penny because a head is showing. Therefore, he says there is a 50-50 chance of it being the two-headed coin.
Should you take the bet? Explain your answer.
Answer by lynnlo(4176) (Show Source): You can put this solution on YOUR website!
take the bet,because you have 3 in 2 chances of winning,since
you will have 3heads in the game
RELATED QUESTIONS
What is the logical conclusion, based on the information given in the problem below?... (answered by macston)

The bowling alley on wedge street charges $5.50 for shoe rental plus $2.50 per game. The... (answered by josmiceli)

Travelling north on the Lexington Avenue Subway, Astor Place is 3 stops after Canal... (answered by Fombitz)

Elliott street is 24ft wide when it ends at main street in brattleboro, vermont, a 40 ft (answered by ankor@dixie-net.com,KMST)

I am trying to help my daughter with the following problem: C Street has an x-intercept... (answered by algebrapro18)

The bowling alley on Wedge Street charges $5.00 for shoe rental plus $1.50 per game.The... (answered by John10)

i need help with the following problem that I was given in my class: When put on a... (answered by josgarithmetic,MathTherapy)

Tripper lives in a house on a straight street. For years, there have been 16 houses on... (answered by mccravyedwin)

ok im sorry about all this but to get to the answer to my question i have to tell you... (answered by funmath)