SOLUTION: I am struggling with helping my son on his homework. The problem seems to be missing a quantifying statement to will help delineate the problem. The problem reads as follows: "

Question 675515: I am struggling with helping my son on his homework. The problem seems to be missing a quantifying statement to will help delineate the problem. The problem reads as follows:
" Tickets for a school dance cost $7 in advance and $11 at the door. If 109 students attended the dance and the total spent was $887, how many tickets were bought in advance and how many at the door?"
Thanks in advance
Kevin
Found 2 solutions by ReadingBoosters, MathLover1:
Answer by ReadingBoosters(3246) (Show Source): You can put this solution on YOUR website!
x = advance
y = door
...
x+y = 109
7x+11y=887
...
rearrange the first equation as x = 109 - y and substitute into the second equation.
...
7(109-y) + 11y = 887
763 - 7y + 11y = 887
4y = 887 - 763
4y = 124
tickets sold at the door
...
x = 109 - 31 = tickets in advance
.....................
Delighted to help.
-Reading Boosters
Email: HomeworkHelpers@ReadingBoosters.com
Wanting for others what we want for ourselves.

Answer by MathLover1(20849) (Show Source): You can put this solution on YOUR website!

stands for advanced tickets
stands for door tickets
....eq. 1 ...than
.........eq. 2
Now substitute in for in the equation 2
...solve for

now substitute in eq.1 for and find

Now check:

(correct)

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