SOLUTION: Katie has a collection of nickels, dimes and quarters with a total value of $6.10 . There are 5 more dimes than nickels and 8 more quarters than nickels, how many of each coin do
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Question 660896: Katie has a collection of nickels, dimes and quarters with a total value of $6.10 . There are 5 more dimes than nickels and 8 more quarters than nickels, how many of each coin does she have?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Katie has a collection of nickels, dimes and quarters with a total value of $6.10 . There are 5 more dimes than nickels and 8 more quarters than nickels, how many of each coin does she have?
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Value equation: 5n + 10d + 25q = 610
Quantity equation: d = n + 5
Quantity equation: q = n + 8
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Substitute for d and q and solve for "n":
5n + 10(n+5) + 25(n+8) = 610
40n + 250 = 610
40n = 360
n = 9 (# of nickels)
d = n+5 = 14 (# of dimes)
q = n+8 = 17 (# of quarters)
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Cheers,
Stan H.
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