SOLUTION: there are 39 coins in a box. the number of dimes is 3 less than twice the number of nickles. how many of each type are there?

Question 659652: there are 39 coins in a box. the number of dimes is 3 less than twice the number of nickles. how many of each type are there?

Answer by ReadingBoosters(3246) (Show Source): You can put this solution on YOUR website!
x = nickles
y = dimes
x + y = 39
y = 2x - 3
Substitute the second equation into the first.
x + 2x - 3 = 39
Combine like terms
3x - 3 + 3 = 39 + 3
3x = 42
3x/3 = 42/3
x = 14 nickles
Plug x into the second equation to solve for y
y = 2(14) - 3
y = 28 - 3
y = 25 dimes
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