SOLUTION: Mike has 7 more nickles than quarters. In all he has $1.25. How man nickles does he have? I'm stuck again!

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Question 64036: Mike has 7 more nickles than quarters. In all he has $1.25. How man nickles does he have?
I'm stuck again!
Found 3 solutions by josmiceli, checkley71, funmath:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
n = number of nickels
q = number of quarters
n+=+q+%2B+7 given
5n+%2B+25q+=+125 given
multiply both sides of 1st by 5
5n+-+5q+=+35 now subtract
-5n+-+25q+=+-125
-30q+=+-90
q+=+3
n+=+q+%2B+7
n+=+3+%2B+7
n+=+10
He has 3 quarters and 10 nickels
check
5n+%2B+25q+=+125
5%2A10+%2B+25%2A3+=+125
50+%2B+75+=+125
125+=+125
OK

Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
LET X BE THE NUMBER OF QUARTERS & (X+7) NICKLES THEN
25X+5(X+7)=125
25X+5X+35=125
30X=125-35
30X=90
X=90/30
X=3 QUARTERS THEN YOU HAVE 3=7=10 NICKLES
PROOF
3*25+10*5=125
75+50=125
125=125

Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
Mike has 7 more nickles than quarters. In all he has $1.25. How man nickles does he have?
Let the number of quarters be: x
Then the amount of money in quarters: .25x
Then the number of nickels are: x+7
and the amount of money in nickels is: .05(x+7)
The total money is: 1.25
Problem to solve is:
.25x+.05(x+7)=1.25
.25x+.05x+.35=1.25
.30x+.35=1.25
.30x+.35-.35=1.25-.35
.30x=.90
.30x/.30=.90/.30
x=3 <--that's the number of quarters
The number of nickels: x+7=3+7=10
Sanity Check:
If you have 3 quarters and 10 nickels, do you have $1.25?
3(.25)+10(.05)=1.25
.75+.50=1.25
1.25=1.25 Yes!
Happy Calculating!!!