SOLUTION: I would appreciate it very much if I could get help with this problem. A vending machine's coin box contains nickels, dimes, and quarters. The total number of coins in the box is

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n+d+q=300;
d=3*(n+q);
25q+10d+5n=3005
d = 225, n = 56, q = 19

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Let = number of nickels
Let = number of dimes
Let = number of quarters
given:
(1)
(2)
(3) ( in cents )
-----------------------==
(2)
Substitute this into (1)
(1)
(1)
(1)
(1)
Substitute this into (3)
(3)
(3)
(3)
(3)
Substitute this back into (1)
(1)
(1)
(1)
(1)
(1)
and, since
(1)
(1)
(1)
and
(3)
(3)
(3)
There are 56 nickels, 225 dimes, and 19 quarters
check answer:
(3)
(3)
(3)
(3)
OK- you can check the other 2 equations