# SOLUTION: Please Help i'd greatly appreciate it! Bob has a coin jar containing nickels, quarters, and one dollar coins. He has a total of 44 coins totaling \$9.75. And, he has five times

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 Click here to see ALL problems on Word Problems With Coins Question 620082: Please Help i'd greatly appreciate it! Bob has a coin jar containing nickels, quarters, and one dollar coins. He has a total of 44 coins totaling \$9.75. And, he has five times as many nickels as he has one dollar coins. How many of each coin does he have? Write a system of equations that can be used to solve this problem. Define what your variables represent. (Nickel \$.05, Quarter \$.25) Thanks you!Found 2 solutions by stanbon, Edwin McCravy:Answer by stanbon(57361)   (Show Source): You can put this solution on YOUR website!Bob has a coin jar containing nickels, quarters, and one dollar coins. He has a total of 44 coins totaling \$9.75. And, he has five times as many nickels as he has one dollar coins. How many of each coin does he have? ---- Quantity Eq::: n + q + d = 44 coins Value Eq::::: 5n +25q +100d= 975 cents Quantity Eq:: n + 0 - 5d = 0 ----------------------- Solve the system anyway you can to get: n = 25 q = 14 d = 5 =========== Cheers, Stan H. =========== Answer by Edwin McCravy(8909)   (Show Source): You can put this solution on YOUR website!Please Help i'd greatly appreciate it! Bob has a coin jar containing nickels, quarters, and one dollar coins. He has a total of 44 coins totaling \$9.75. And, he has five times as many nickels as he has one dollar coins. How many of each coin does he have? Write a system of equations that can be used to solve this problem. Define what your variables represent. (Nickel \$.05, Quarter \$.25) Thanks you! ```Let the number of dollar coins be D ``` >>...he has five times as many nickels as he has one dollar coins...<< ```So the number of nickels is 5D Let Q = the number of quarters. ``` >>...He has a total of 44 coins...<< ```Therefore D + 5D + Q = 44 or 6D + Q = 44 ``` >>...totaling \$9.75...<< ```So 1.00D + .25Q + .05(5D) = 9.75 or 1.00D + .25Q + .25D = 9.75 or multiplying through by 100, 100D + 25Q + 25D = 975 or combining like terms 125D + 25Q = 975 or dividing through by 25 5D + Q = 39 So we have this system of equations: 6D + Q = 44 5D + Q = 39 -------------- Solve that system and get D=5, Q=14 So there are 5 dollar coins, 14 quarters, and since the number of nickels is 5D, that's 5(5) or 25 nickels. Edwin```