SOLUTION: Jim has a jar of dimes, nickels, and pennies. He has one dime more than five times the number of nickels and four times as many pennies as nickels. How many of each coin are in the

Question 58388: Jim has a jar of dimes, nickels, and pennies. He has one dime more than five times the number of nickels and four times as many pennies as nickels. How many of each coin are in the jar if the total value is $7.77?
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
d = 5n + 1
4n = p
10d + 5n + p = 777
10(5n + 1) + 5n + 4n = 777
50n + 10 + 5n + 4n = 777
59n = 777
n = 13
d = 66
p = 52
check
10(66) + 5(13) + 52 = 777
660 + 65 + 52 = 777
777 = 777
OK
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