SOLUTION: a newspaper carrier has $4.25 in change. He has seven more quarters than dimes but four times as many nickels as quarters. How many coins of each type does he have?

Question 572915: a newspaper carrier has $4.25 in change. He has seven more quarters than dimes but four times as many nickels as quarters. How many coins of each type does he have?
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
let dimes be x
quarters = x+7
nickels = 4(x+7)
the value = $4.25 = 425cents
value equation
10x+25(x+7)+5*4(x+7)=425
10x+25x+175+20x+140=425
55x+315=425
55x= 425-315
55x=110
x= 2
2 dimes
quarters =(2+7)=9
nickels = 4(x+7)=4*9=36
CHECK
36*5 + 9*25+2*10=
180+225+20=425
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