There are only two ways to have 67 cents in 6 coins: 1. 1 half dollar, 3 nickels and 2 pennies 2. 2 quarters, 1 dime, 1 nickel and 2 pennies However, since half dollars are not in circulation, there is just one way: 2 quarters, 1 dime, 1 nickel and 2 pennies We want P(nickel first AND quarter second) = P( "1 way out of 6 or" AND "2 ways out of 5 or ) = × = = Edwin