# SOLUTION: A man has two kinds of money, dimes and half dimes. If he is offered \$1.35 for 20 coins, how many of each kind must he give?

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 Question 548333: A man has two kinds of money, dimes and half dimes. If he is offered \$1.35 for 20 coins, how many of each kind must he give?Answer by mananth(12270)   (Show Source): You can put this solution on YOUR website!dimes x nickels y Total 750 1 x + 1 y = 20 .............1 10 x + 5 y = 135 .............2 Eliminate y multiply (1)by -5 Multiply (2) by 1 -5 x -5 y = -100 10 x + 5 y = 135 Add the two equations 5 x = 35.00 / 5 x = 7 plug value of x in (1) 1 x + 1 y = 20 7 + 1 y = 20 1 y = 20 -7 1 y = 13 y = 13