SOLUTION: A man has two kinds of money, dimes and half dimes. If he is offered $1.35 for 20 coins, how many of each kind must he give?

Algebra ->  Algebra  -> Customizable Word Problem Solvers  -> Coins -> SOLUTION: A man has two kinds of money, dimes and half dimes. If he is offered $1.35 for 20 coins, how many of each kind must he give?      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com
Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!
Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!

   


Question 548333: A man has two kinds of money, dimes and half dimes. If he is offered $1.35 for 20 coins, how many of each kind must he give?
Answer by mananth(12270) About Me  (Show Source):
You can put this solution on YOUR website!
dimes x
nickels y
Total 750
1 x + 1 y = 20 .............1
10 x + 5 y = 135 .............2
Eliminate y
multiply (1)by -5
Multiply (2) by 1
-5 x -5 y = -100
10 x + 5 y = 135
Add the two equations
5 x = 35.00
/ 5
x = 7
plug value of x in (1)
1 x + 1 y = 20
7 + 1 y = 20
1 y = 20 -7
1 y = 13
y = 13