SOLUTION: You have 100 coins in nickels,dimes, and quarters. The value of the coins is $21.25. You have 3 more nickels than dimes. What are the three equations that you would use to solve th

Question 531081: You have 100 coins in nickels,dimes, and quarters. The value of the coins is $21.25. You have 3 more nickels than dimes. What are the three equations that you would use to solve this problem?
Answer by oberobic(2304) (Show Source): You can put this solution on YOUR website!
n + d + q = 100
.
5n +10d +25q = 2125
.
n = d+3
.
d+3 +d +q = 100
2d + q = 97
.
5(d+3) + 10d + 25q = 2125
5d +15 +10d + 25q = 2125
15d +25q = 2110
.
2d + q = 97
15d +25q = 2110
.
50d + 25q = 2425
15d + 25q = 2110
------------------ subtract
35d = 315
.
d = 115/35
d = 9 dimes
.
n = d+3 = 12 nickels
.
q = 100 -9 -12
q = 79 quarters
.
Check the values to determine if the answer is correct.
12(5) + 10(9) + 25(79) = 2125 ??
Yes.
.
Answer: 12 nickels, 9 dimes, and 79 quarters

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