SOLUTION: Mr.Bob cashed $185 in his bank. He received $1 bills, $5 bills,and $10 bills
in this order.the numbers of these three types of bills he received were three consecutive integers. H
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Question 530953: Mr.Bob cashed $185 in his bank. He received $1 bills, $5 bills,and $10 bills
in this order.the numbers of these three types of bills he received were three consecutive integers. How many bills of each type did he receive?
Found 2 solutions by oberobic, stanbon:
Answer by oberobic(2304) (Show Source): You can put this solution on YOUR website!
3 consecutive integers can be defined as:
x
x+1
x+2
.
We're told these correspond to $1 bills, $5 bills, and $10 bills.
.
x + 5(x+1) + 10(x+2) = 185
.
x +5x +5 + 10x + 20 = 185
.
16x + 25 = 185
.
16x = 160
.
x = 10 = number of $1 bills
x+1 = 11 = number of $5 bills
x+2 = 12 = number of $10 bills
.
Check the value to be sure this is the answer.
1(10) + 5(11) + 10(12) = 10 + 55 + 120 = 185
Correct.
.
Done.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Mr.Bob cashed $185 in his bank. He received $1 bills, $5 bills,and $10 bills
in this order.the numbers of these three types of bills he received were three consecutive integers. How many bills of each type did he receive?
-----
# of $1 bills: x-1
# of $5 bills: x
# of #10bills: x+1
-----
Value Equation:
1*(x-1) + 5*x + 10*(x+1) = 185 dollars
------
x-1 + 5x + 10x + 10 = 185
16x = 176
x = 11
----
# of $1 bills = x-1 = 11-1 = 10
----
# of $5 bills = 11
----
# of $10 bills = x+1 = 12
=================================
Cheers,
Stan H.
============
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