SOLUTION: Peggy had four times as many quarters as nickels. She had $2.10 in all. How many nickels and how many quarters did she have? Which of the following equations could be used to so

Question 526392: Peggy had four times as many quarters as nickels. She had $2.10 in all. How many nickels and how many quarters did she have?
Which of the following equations could be used to solve the problem?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Peggy had four times as many quarters as nickels. She had $2.10 in all. How many nickels and how many quarters did she have?
Which of the following equations could be used to solve the problem?
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Quantity Equation: q = 4n
Value Equation: 5n + 25q = 210 cents
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Substitute for "q" and solve for "n":
5n + 25(4n) = 210
5n + 100n = 210
105n = 210
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n = 2 (# of nickels)
---
Solve for "q":
q = 4n
q = 4*2 = 8 (# of quarters)
==================================
Cheers,
Stan H.
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