SOLUTION: One night a waiter recieved $11.30 in tips-all coins. He had 3 times as many dimes as nickels, and 10 more quarters than dimes. Find the number of each type of coin. I dont tr

Question 524851: One night a waiter recieved $11.30 in tips-all coins. He had 3 times as many dimes as nickels, and 10 more quarters than dimes. Find the number of each type of coin.

I dont truly understand how to find the formula for this -__- plzz help!!!!

Found 2 solutions by mananth, josmiceli:
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
nickels = n
dimes = 3n
quarters = 3n+10

$11.30 = 1130 cents
5n+10*3n+25(3n+10)=1130
5n+30n+75n+250=1130
110n=1130-250
110n=880
/110
n=8 nickels
dimes = 3n = 24 dimes
quarters = 3n+10= 34
Check
34*25 + 24*10+8*5 = 1130
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Let = number of dimes
Let = number of nickels
Let = number of quarters
given:
(1)
(2)
(3) ( in cents )
This is 3 equations with 3 unknowns,
so it's solvable
-------------------
(1)
Substitute (1) and (2) into (3)
(3)
(3)
Multiply both sides by
(3)
(3)
(3)
(3)
and, since
(1)
(1)
(1)
also,
(2)
(2)
(2)
There are 24 dimes, 8 nickels, and 34 quarters
check:
(3)
(3)
(3)
(3)
OK
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