SOLUTION: Paul has $3.05 in nickels and dimes. He has ten more nickels than dimes. How many of each coin does he have?

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Question 515534: Paul has $3.05 in nickels and dimes. He has ten more nickels than dimes. How many of each coin does he have?
Answer by oberobic(2304)   (Show Source): You can put this solution on YOUR website!
n = number of nickels
5n = value of nickels in cents
d = number of dimes
10d = value of dimes in cents
.
5n + 10d = 305 cents
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n = d+10
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substitute
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5(d+10) + 10d = 305
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5d +50 +10d = 305
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15d = 255
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d = 255/15 = 17
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n = d+10 = 27
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Check the values to be sure this is the answer.
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5(17) = 85
10(27) = 270
85 + 270 = 355
Correct
.
Answer: He has 17 dimes and 27 nickels.
.
Done.

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