SOLUTION: A bag of coins contains dimes, pennies, and nickels. There are five more dimes than nickels. There are three times as many pennies as nickels. The bag contains $8.78. How m

Question 513440: A bag of coins contains dimes, pennies, and nickels. There are
five more
dimes than nickels. There are three times as many pennies as
nickels.
The bag contains $8.78. How many nickels are in the bag?
Answer by oberobic(2304) (Show Source): You can put this solution on YOUR website!
p = number of pennies
1p = value of the pennies in cents
n = number of nickels
5n = value of nickels in cents
d = number of dimes
10d = value of dimes in cents.
.
d = n+5
.
p = 3n
.
1p + 5n + 10d = 878 cents
.
3n + 5n + 10(n+5) = 878
.
8n + 10n +50 = 878
.
18n = 828
.
n = 46
.
p = 3n
.
p = 3*46 = 138
.
d = n+5 = 46 +5 = 51
.
Always check your solution.
.
1(138) = $1.38
5(46) = $2.30
10(51) = $5.10
$1.38 + $2.30 + $5.10 = $8.78
Correct.
.
Always re-read the question to make sure you answer it.
.
Answer: There are 46 nickels in the bag.
.
Done.

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