SOLUTION: Josiah has three less than twice as many nickles as dimes. If the total value of hsi coins was $1.45 how many of each kind of coin did he have?

Question 509404: Josiah has three less than twice as many nickles as dimes. If the total value of hsi coins was $1.45 how many of each kind of coin did he have?
Answer by oberobic(2304) (Show Source): You can put this solution on YOUR website!
n = number of nickels
5n = value of nickels in cents
d = number of dimes
10d = value of dimes in cents
.
n = 2d -3
.
5n + 10d = 145 cents
.
substitute
.
5(2d-3) + 10d = 145
.
10d -15 + 10d = 145
.
20d = 160
.
d = 8
.
n = 2(8) -3
.
n = 13
.
Check the value to see if this is the correct answer.
.
5(13) + 10(8) = 65 + 80 = 145
Correct.
.
Answer: Josiah has 8 dimes and 13 nickels.
.
Done.
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