SOLUTION: Sue has $2.50 in dimes and nickels. If she has 10 more dimes than nickels, how many of each coin does she have?

Question 499401: Sue has $2.50 in dimes and nickels. If she has 10 more dimes than nickels, how many of each coin does she have?
Answer by oberobic(2304) (Show Source): You can put this solution on YOUR website!
With coin problems, you have to keep track of the count of coins and their values.
d = number of dimes
10d = value of dimes in cents
n = number of nickels
5n = value of nickels in cents
.
5n + 10d = 250 cents
.
She has 10 more dimes than nickels.
d = n+10
.
substitute
5n + 10(n+10) = 250
5n +10n + 100 = 250
collect
15n + 100 = 250
15n = 150
n = 10
.
d = n+10
d = 10+10
d = 20
.
Check your work by checking the values:
5n = 5(10) = 50 cents
10d = 10(20) = 200 cents
total = 250 cents
correct
.
She has 10 nickels and 20 dimes.
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