SOLUTION: PLEASE HELP!!! Shopkeeper moneypenny needs coins. he wants the same amount of the following coins, i.e he wants to have coins with the value of 1,2,5,10,20,50 cent and 1 euro. H

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Question 498996: PLEASE HELP!!!
Shopkeeper moneypenny needs coins. he wants the same amount of the following coins, i.e he wants to have coins with the value of 1,2,5,10,20,50 cent and 1 euro.
He wants to change 282 euro into coins. is it possible to have the same amount of the different coins, and if it is, How many coins all together, will he get
Found 2 solutions by Edwin McCravy, ankor@dixie-net.com:
Answer by Edwin McCravy(20059)   (Show Source): You can put this solution on YOUR website!
 

Let that same amount of coins of each kind be x.

Then

.01x + .02x + .05x + .10x + .20x + .50x + 1.00x = 282.00

                                          1.88x = 282.00

                                              x = 

                                              x = 150

Yes, it is possible to have 150 each of the 7 coins.  
That will be 150×7 or 1050 coins.

Edwin
Answer by ankor@dixie-net.com(22740)   (Show Source): You can put this solution on YOUR website!
Shopkeeper moneypenny needs coins. he wants the same amount of the following coins, i.e he wants to have coins with the value of 1,2,5,10,20,50 cent and 1 euro.
He wants to change 282 euro into coins.
is it possible to have the same amount of the different coins, and if it is,
How many coins all together, will he get
:
Let's see if it is possible; let n = number of each coin
:
.01n + .02n +.05n + .10n + .20n + .50n + 1n = 282
Add all them n's and we have
1.88n = 282
n =
n = 150 coins of each value
:
Their are seven kinds of coins: 7 * 150 = 1050 coins in all
:
Not that hard, right?
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